87 lines
2.8 KiB
Python
87 lines
2.8 KiB
Python
# vim: ft=python fileencoding=utf-8 sts=4 sw=4 et:
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# Copyright 2014-2015 Florian Bruhin (The Compiler) <mail@qutebrowser.org>
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#
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# This file is part of qutebrowser.
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#
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# qutebrowser is free software: you can redistribute it and/or modify
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# it under the terms of the GNU General Public License as published by
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# the Free Software Foundation, either version 3 of the License, or
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# (at your option) any later version.
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#
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# qutebrowser is distributed in the hope that it will be useful,
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# but WITHOUT ANY WARRANTY; without even the implied warranty of
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# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
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# GNU General Public License for more details.
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#
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# You should have received a copy of the GNU General Public License
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# along with qutebrowser. If not, see <http://www.gnu.org/licenses/>.
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"""Other utilities which don't fit anywhere else."""
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import os.path
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from qutebrowser.utils import log
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from qutebrowser.browser import rfc6266
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from PyQt5.QtNetwork import QNetworkRequest
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def parse_content_disposition(reply):
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"""Parse a content_disposition header.
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Args:
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reply: The QNetworkReply to get a filename for.
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Return:
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A (is_inline, filename) tuple.
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"""
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is_inline = True
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filename = None
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content_disposition_header = 'Content-Disposition'.encode('iso-8859-1')
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# First check if the Content-Disposition header has a filename
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# attribute.
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if reply.hasRawHeader(content_disposition_header):
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# We use the unsafe variant of the filename as we sanitize it via
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# os.path.basename later.
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try:
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content_disposition = rfc6266.parse_headers(
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bytes(reply.rawHeader(content_disposition_header)))
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filename = content_disposition.filename()
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except UnicodeDecodeError:
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log.rfc6266.exception("Error while decoding filename")
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else:
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is_inline = content_disposition.is_inline()
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# Then try to get filename from url
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if not filename:
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filename = reply.url().path()
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# If that fails as well, use a fallback
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if not filename:
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filename = 'qutebrowser-download'
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return is_inline, os.path.basename(filename)
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def parse_content_type(reply):
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"""Parse a Content-Type header.
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The parsing done here is very cheap, as we really only want to get the
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Mimetype. Parameters aren't parsed specially.
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Args:
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reply: The QNetworkReply to handle.
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Return:
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A [mimetype, rest] list, or [None, None] if unset.
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Rest can be None.
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"""
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content_type = reply.header(QNetworkRequest.ContentTypeHeader)
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if content_type is None:
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return [None, None]
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if ';' in content_type:
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ret = content_type.split(';', maxsplit=1)
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else:
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ret = [content_type, None]
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ret[0] = ret[0].strip()
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return ret
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