# vim: ft=python fileencoding=utf-8 sts=4 sw=4 et: # Copyright 2017-2018 Florian Bruhin (The Compiler) # # This file is part of qutebrowser. # # qutebrowser is free software: you can redistribute it and/or modify # it under the terms of the GNU General Public License as published by # the Free Software Foundation, either version 3 of the License, or # (at your option) any later version. # # qutebrowser is distributed in the hope that it will be useful, # but WITHOUT ANY WARRANTY; without even the implied warranty of # MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the # GNU General Public License for more details. # # You should have received a copy of the GNU General Public License # along with qutebrowser. If not, see . import string import functools import operator import pytest import qutebrowser.browser.hints @pytest.mark.parametrize('min_len', [0, 3]) @pytest.mark.parametrize('num_chars', [9]) @pytest.mark.parametrize('num_elements', range(1, 26)) def test_scattered_hints_count(win_registry, mode_manager, min_len, num_chars, num_elements): """Test scattered hints function. Tests many properties from an invocation of _hint_scattered, including 1. Hints must be unique 2. There can only be two hint lengths, only 1 apart 3. There are no unique prefixes for long hints, such as 'la' with no 'l' """ manager = qutebrowser.browser.hints.HintManager(0, 0) chars = string.ascii_lowercase[:num_chars] hints = manager._hint_scattered(min_len, chars, list(range(num_elements))) # Check if hints are unique assert len(hints) == len(set(hints)) # Check if any hints are shorter than min_len assert not any(x for x in hints if len(x) < min_len) # Check we don't have more than 2 link lengths # Eg: 'a' 'bc' and 'def' cannot be in the same hint string hint_lens = {len(h) for h in hints} assert len(hint_lens) <= 2 if len(hint_lens) == 2: # Check if hint_lens are more than 1 apart # Eg: 'abc' and 'd' cannot be in the same hint sequence, but # 'ab' and 'c' can assert abs(functools.reduce(operator.sub, hint_lens)) <= 1 longest_hints = [x for x in hints if len(x) == max(hint_lens)] if min_len < max(hint_lens) - 1: # Check if we have any unique prefixes. For example, 'la' # alone, with no other 'l' count_map = {} for x in longest_hints: prefix = x[:-1] count_map[prefix] = count_map.get(prefix, 0) + 1 assert all(e != 1 for e in count_map.values())