ex-3: review
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@ -388,40 +388,47 @@ Likelihood results:
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----------------------------
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par $p$-value
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par $p$-value
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------------ ---------------
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------------ ---------------
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$\alpha_L$ 0.18
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$α_L$ 0.18
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$\beta_L$ 0.55
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$β_L$ 0.55
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$\gamma_L$ 0.023
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$γ_L$ 0.023
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----------------------------
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----------------------------
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Table: Likelihood results compatibility.
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Table: Likelihood results compatibility.
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$\chi^2$ results:
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$\chi^2$ results:
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---------------------------------
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----------------------------
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par $p$-value
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par $p$-value
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----------------- ---------------
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------------ ---------------
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$\alpha_{\chi}$ 0.22
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$α_χ$ 0.22
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$\beta_{\chi}$ 0.89
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$β_χ$ 0.89
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$\gamma_{\chi}$ 0.0001
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$γ_χ$ 0.0001
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---------------------------------
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----------------------------
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Table: $\chi^2$ results compatibility.
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Table: $\chi^2$ results compatibility.
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It can be concluded that only the third parameter, $\gamma$ is not compatible
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It can be concluded that, with both methods, the parameters $\alpha$ and $\beta$
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with the expected one in both cases. An in-depth analysis of the algebraic
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were recovered succefully, while $\gamma$ is incompatible. However, the
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arrangement of $F$ would be required in order to justify this outcome.
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covariance was estimated using the Cramér-Rao bound, so the errors may be
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underestimated, which must be the case for $\gamma$.
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Since two different methods similarly underestimated the true value of
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$\gamma$, it was suspected the Monte Carlo simulation was faulty. This
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phenomenon was observed frequently when generating multiple samples, so it
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can't be attributed to statistical fluctuations in that particular sample.
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The issue remains unsolved as no explanation was found.
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\vspace{30pt}
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## Isotropic hypothesis testing
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## Isotropic hypothesis testing
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What if the probability distribution function was isotropic? Could it be
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What if the probability distribution function were isotropic?
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compatible with the found results?
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Is this hypothesys compatible with the observation?
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If $F$ was isotropic, then $\alpha_I$, $\beta_I$ and $\gamma_I$ would be $1/3$
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, 0, and 0 respectively, since this gives $F_I = 1/{4 \pi}$. The t-test gives a
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If $F$ is isotropic, $\alpha_I$, $\beta_I$ and $\gamma_I$ would be $1/3$ , 0,
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$p$-value approximately zero for all the three parameters, meaning that there is
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and 0 respectively, since this gives $F_I = 1/{4 \pi}$. The t-test gives a
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no compatibility at all with this hypothesis.
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$p$-value approximately zero for all the three parameters, meaning that there
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is no compatibility at all with this hypothesis.
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