sec-3: change √8 into 2√2

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Giù Marcer 2020-06-12 22:17:21 +02:00 committed by rnhmjoj
parent c39e0190aa
commit 9476aab2f1

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@ -119,7 +119,7 @@ $$
We need to compute the maximum value:
$$
M(\mu_M\ex) = \frac{1}{\sqrt{2 \pi e}} \thus M(x_{\pm}) = \frac{1}{\sqrt{8 \pi e}}
M(\mu_M\ex) = \frac{1}{\sqrt{2 \pi e}} \thus M(x_{\pm}) = \frac{1}{2 \, \sqrt{2 \pi e}}
$$
. . .