sec-3: change √8 into 2√2
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@ -119,7 +119,7 @@ $$
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We need to compute the maximum value:
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$$
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M(\mu_M\ex) = \frac{1}{\sqrt{2 \pi e}} \thus M(x_{\pm}) = \frac{1}{\sqrt{8 \pi e}}
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M(\mu_M\ex) = \frac{1}{\sqrt{2 \pi e}} \thus M(x_{\pm}) = \frac{1}{2 \, \sqrt{2 \pi e}}
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$$
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. . .
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