ex-6: went on writing about the RL deconvolution
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@ -318,6 +318,55 @@ necessary to rearrange the two halfs of the final result.
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At the end, the external bins which exceed with respect to the original signal
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are cut away in order to restore the original number of bins $n$.
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## Unfolding with Richardson-Lucy
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The Richardson–Lucy deconvolution is an iterative procedure usually used for
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recovering an image that has been blurred by a known point spread function.
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It is based on the fact that an ideal point source does not appear as a point
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but is spread out into the so-called point spread function, thus the observed
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image can be represented in terms of a transition matrix
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$P$ operating on an underlying image:
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$$
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d_i = \sum_{j} P_{i, j} u_j
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$$
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where $u_j$ is the intensity of the underlying image at pixel $j$ and $d_i$ is
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the detected intensity at pixel $i$. In general, a matrix whose elements are
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$P_{i,j}$ describes the portion of signal from the source pixel $j$ that is
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detected in pixel $i$.
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In one dimension, the transfer function
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can be expressed in terms of the distance between the source pixel $j$ and the
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observed $i$:
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$$
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P_{i, j} = \widetilde{P}(i-j)
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$$
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In order to estimate $u_j$ given the observed $d_i$ and a known $\widetilde{P}$,
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the following iterative procedure for the estimate $\hat{u}^t_j$ of $u_j$ can
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be applied. The $t^{\text{th}}$ iteration is updated as follows:
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$$
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\hat{u}^{t+1}_j = \hat{u}^t_j \sum_i \frac{d_i}{c_i} \, P_{ij}
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\with c_i = \sum_j P_{ij} {\hat{u^t}}_j.
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$$
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It has been shown empirically that if this iteration converges, it converges to
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the maximum likelihood solution for $u_j$.
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Writing this more generally in terms of convolution with a point spread function
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$\tilde{P}$ it becomes:
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$$
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\hat{u}^{t+1} = \hat {u}^{t} \cdot \left( \frac{d}{{\hat{u}^{t}} \otimes
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\widetilde{P}} \otimes \widetilde{P}^{\star} \right)
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$$
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where the division and multiplication are element wise, and
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$\widetilde{P}^{\star}$ is the flipped point spread function.
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---
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<div id="fig:convolved">
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