From 527f1fcfce415e425dd533f2af4f2a5d7d439ccc Mon Sep 17 00:00:00 2001
From: rnhmjoj <rnhmjoj@inventati.org>
Date: Mon, 6 Jul 2020 16:29:22 +0200
Subject: [PATCH] notes: fix mistake in ex-2 computation

---
 notes/sections/2.md | 4 ++--
 1 file changed, 2 insertions(+), 2 deletions(-)

diff --git a/notes/sections/2.md b/notes/sections/2.md
index bb679d0..7fda7f2 100644
--- a/notes/sections/2.md
+++ b/notes/sections/2.md
@@ -249,8 +249,8 @@ $W$ both sides.
 \begin{align*}
 \frac{5 \sqrt{2 \pi}}{12 \sqrt{x}} e^{-8x} = 10^{-D}
   & \thus \left(\frac{12}{5}\right)^2 \frac{x}{2 \pi} e^{16x} = 10^{2D} \\
-  & \thus 16x e^{16x} = \left(\frac{5 \pi}{9}\right)^2 10^{2D + 1}      \\
-  & \thus x = \frac{1}{16} W\left(\left(\frac{5 \pi}{9}\right)^2 10^{2D + 1}\right)
+  & \thus 16x e^{16x} = \frac{5 \pi}{9} 10^{2D + 1}      \\
+  & \thus x = \frac{1}{16} W\left(\frac{5 \pi}{9} 10^{2D + 1}\right)
 \end{align*}
 The smallest integer which satisfies the inequality is then
 $$